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Your friend comes across a good deal to purchase a gold ring. She asks you for advice and for you to test the ring. The ring has a mass of a 4.54 g. When you heat the ring with 94.8 J of energy, its temperature rises from 23.0°C to 47.5°C. Would you advise your friend that she is getting a good deal? Explain. The specific heat capacity of gold is 0.1291 J/g•°C.

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AMB000

Answer:

She is not getting a good deal.

Explanation:

The equation that relates heat with mass, specific heat and temperature change of an object is [tex]Q=mc\Delta T[/tex].

Always convert temperature to Kelvin, although in our case it's not necessary because the [tex]\Delta T[/tex] will be the same, and we will leave the mass in grams because we will be getting [tex]J/g^{\circ}C[/tex] units for specific heat, which we can compare to the one given for gold.

We then calculate the specific heat of the object in question:

[tex]c=\frac{Q}{m\Delta T}=\frac{94.8J}{(4.54g)(47.5^{\circ}C-23^{\circ}C)}=0.8523 J/g^{\circ}C[/tex]

Which shows it's not gold.

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