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A ball of mass m, attached to the end of a horizontal cord, is rotated in a circle of radius r on a frictionless horizontal surface. If the cord will break when the tension in it exceeds F, what is the maximum speed the ball can have? Express your answer in terms of the given quantities.

Respuesta :

Answer:[tex]v=\sqrt{\frac{FL}{m}}[/tex]

Explanation:

Given

Ball of mass m

maximum Bearable Tension in string is F

Let length of the cord be L m and moving at a speed of v m/s

Here Tension will Provide Centripetal Force

T=Centripetal Force

[tex]F=T=\frac{mv^2}{L}[/tex]

[tex]v=\sqrt{\frac{FL}{m}}[/tex]

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