Respuesta :
Answer:
0.15 m/s² east
Explanation:
We can use following kinematic equation for Uniformly-Accelerated Motion to solve this problem:
v = v₀ + a × t
Where v is the final velocity, v₀ is the initial velocity, a is the acceleration and t is the time interval.
The data of the problem is:
- v₀ = - 100km/h (remember to have a frame of reference, I decided traveling west will be towards the negative values and traveling east will be positive).
- v = 0 km/h (the car comes to a full stop)
- t = 3 min
Replacing the data in the formula:
0 km/h = -100 km/h + a × 3 min
It's very important to use the same units when solving problems. I will convert kilometer to meters and hour or minutes to seconds, because the answer choices are given in m/s².
- 0 km/h = 0 m/s
- [tex]\frac{100 \ km}{\ \ h} * \frac{1000\ m}{1\ km} * \frac{1\ \ h}{3600\ s} = \frac{27.78\ m}{\ \ \ \ s}[/tex]
- [tex]3 min * \frac{60\ s}{1\ m} = 180 s[/tex]
Then:
[tex] 0 m/s = -27.78 \ m/s + a * 180 s\\+27.78 m/s = a * 180 s\\[/tex]
[tex]\frac{+27.78 \ m/s}{180\ s} = a\\\\+ 0.15 m/s^2 = a[/tex]
And considering our frame of reference, a positive sign indicates that the acceleration is east-bound.