Answer:
The mass of Ag₃PO₄ produce is 12.8 g.
Explanation:
First of all we will write the balance chemical equation;
Na₃PO₄+ 3AgNO₃ → Ag₃PO₄ + 3NaNO₃
Number of moles of Na₃PO₄ = mass / molar mass
Number of moles of Na₃PO₄ = 5.00 g/ 164 g/mol
Number of moles of Na₃PO₄ = 0.0305 mol
Now we compare the moles of Na₃PO₄ and Ag₃PO₄ from balance chemical equation:
Na₃PO₄ : Ag₃PO₄
1 : 1
0.0305 : 0.0305
Mass of Ag₃PO₄:
mass of Ag₃PO₄ = moles × molar mass
mass of Ag₃PO₄ = 0.0305 × 419
mass of Ag₃PO₄ = 12.8 g
