You place an AC voltage signal of amplitude 1.4 V and with a frequency of 1400.0 Hz, into the input of an oscilloscope.

a.) Find the distance displayed on the screen of the oscilloscope for a full wave, if the sweep speed is adjusted to 119 �sec/DIV. (in divisions)

b.) If the vertical gain is set to 0.40 V/DIV, how many divisions will the wave span from peak-to-peak of the wave? (in divisions)

Question

28-10-2019
Physics

contestada

You place an AC voltage signal of amplitude 1.4 V and with a frequency of 1400.0 Hz, into the input of an oscilloscope.

a.) Find the distance displayed on the screen of the oscilloscope for a full wave, if the sweep speed is adjusted to 119 �sec/DIV. (in divisions)

b.) If the vertical gain is set to 0.40 V/DIV, how many divisions will the wave span from peak-to-peak of the wave? (in divisions)

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CarliReifsteck CarliReifsteck · Answer 1 · 2019-10-30T12:50:09+01:00

Answer:

(a). The horizontal distance on the screen is 6 Div.

(b). The number of division from peak to peak is 7 Div.

Explanation:

Given that,

Amplitude = 1.4 V

Frequency = 1400.0 Hz

Vertical gain = 0.40 V/Div

Sweep speed [tex]v= 119 \times10^{-6}\ sec/Div[/tex]

We need to calculate the period

Using formula of period of input voltage

[tex]T=\dfrac{1}{f}[/tex]

Put the value into the formula

[tex]T=\dfrac{1}{1400.0}[/tex]

[tex]T=0.714\times10^{-3}\ sec[/tex]

(a). We need to calculate the distance displayed on the screen of the oscilloscope for a full wave,

[tex]x=\dfrac{T}{v}[/tex]

Here, v = sweep speed

Put the value into the formula

[tex]x=\dfrac{0.714\times10^{-3}}{119\times10^{-6}}[/tex]

[tex]x=6\ Div[/tex]

The horizontal distance on the screen is 6 Div.

(b). We need to calculate the peak to peak vertical amplitude of the wave

Using formula of amplitude

[tex]v_{pp}=2\times Amplitude[/tex]

Put the value into the formula

[tex]v_{pp}=2\times1.4[/tex]

[tex]v_{pp}=2.8\ V[/tex]

We need to calculate the number of division from peak to peak

Using formula of division

[tex]y=\dfrac{v_{pp}}{verical\ gain}[/tex]

Put the value into the formula

[tex]y=\dfrac{2.8}{0.40}[/tex]

[tex]y=7\ Div[/tex]

The number of division from peak to peak is 7 Div.

Hence, (a). The horizontal distance on the screen is 6 Div.

(b). The number of division from peak to peak is 7 Div.