Answer:
The co-ordinates of the vertex of the function y-9= -6(x-1)^2 is (1, 9)
Solution:
Given, equation is [tex]y-9=-6(x-1)^{2}[/tex]
We have to find the vertex of the given equation.
When we observe the equation, it is a parabolic equation,
We know that, general form of a parabolic equation is [tex]y-9=-6(x-1)^{2}[/tex]
Where, h and k are x, y co ordinates of the vertex of the parabola.
[tex]\text { Now, parabola equation is } y-9=-6(x-1)^{2} \rightarrow y=-6(x-1)^{2}+9[/tex]
By comparing the above equation with general form of the parabola, we can conclude that,
a = -6, h = 1 and k = 9
Hence, the vertex of the parabola is (1, 9).
