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Write the standard form of the equation of the circle described below.
Center (0. - 2) passes through the point (-5. - 1)

Respuesta :

The equation of circle is: [tex]x^2+(y+2)^2 = 26[/tex]

Further explanation:

Standard form of equation is:

[tex](x-h)^2+(y-k)^2 = r^2\\[/tex]

Here (h,k) are the coordinates of the centre and r is radius.

As the centre and one point on boundary is given, we have to calculate the radius first.

Distance formula will be used to calculate radius.

[tex]d = r = \sqrt{x_2-x_1)^2+(y_2-y_1)^2}\\ = \sqrt{(-5-0)^2+(-1+2)^2}\\ =\sqrt{(-5)^2+(1)^2}\\ =\sqrt{25+1}\\ =\sqrt{26}[/tex]

Now

(h,k) = (0, -2)

Putting the values of r and (h,k) in standard equation

[tex](x-0)^2+(y-(-2))^2 = (\sqrt{26})^2\\(x)^2+(y+2)^2 = 26\\x^2+(y+2)^2 = 26[/tex]

The equation of circle is:

[tex]x^2+(y+2)^2 = 26[/tex]

Keywords: Equation of Circle, Radius of Circle

Learn more about equation of circle at:

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