Answer:
Step-by-step explanation:
This is your equation:
[tex]\sqrt{3x-2}=4[/tex]
To undo that square root, square both sides, giving you:
3x - 2 = 16. Solving for x gives us
3x = 18 so
x = 6
If you plug 6 back into the equation, the original one, you get that the square root of 16 = 4, which is true.
