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What is the specific heat capacity of silver metal if 55.00 g of the metal
absorbs 47.3 calories of heat and the temperature rises 15.0°C?

Respuesta :

MathPhys

Answer:

0.240 J/g/°C

Explanation:

q = mCΔT

47.3 cal = (55.00 g) C (15.0°C)

C = 0.0573 cal/g/°C

Usually, specific heat is measured in J/g/°C, so we can convert:

C = 0.0573 cal/g/°C × 4.184 J/cal

C = 0.240 J/g/°C

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