Answer:
V2 = 0.066 miles per hour
Explanation:
Let d be the 5 miles distance, V1 the velocity when you go and V2 when you return home.
We know that:
t1 + t2 = 76 (eq1)
V1 = V2 + 9 (eq2)
t1 = d / V1 t2 = d / V2 Replacing this values into eq1:
[tex]\frac{d}{V1} +\frac{d}{V2}=76[/tex] Replacing V1 by its values from eq2:
[tex]\frac{d}{V2+9} +\frac{d}{V2}=76[/tex]
[tex]76*V2^2+674V2-45=0[/tex]
Solving fro V2, we get the result of the problem:
V2 = 0.066mi/h or V2 = -8.93mi/h We discard the negative value and obtain:
V2 = 0.066mi/h
