Answer:
Part A: Time = 0.45 s
Part B: Horizontal distance = 0.5625 m
Explanation:
Part A:
As the ball with a horizontal speed of 1.25 m/s rolls off a bench 1.00 m above the floor, it follow the projectile path.
Projectile motion is a two dimensional motion and the path followed by projectile motion is called projectile path.
Given data:
horizontal velocity = v₍ₓ₎ = 1.25 m/s
vertical velocity = v₍ₙ₎ = 0 m/s
Height = h = 1 m
From 2nd equation of motion
h = v₍ₙ₎t + 0.5 gt²
1 = 0 + 0.5(9.81)t²
2 = 9.81 t²
t = √(0.2)
t = 0.45 s
Part B:
In projectile motion, horizontal component of velocity remain same,
So there is no acceleration in horizontal direction.
We can use the following formula
Horizontal distance = R = v₍ₓ₎t
R = 1.25 × 0.45
R = 0.5625 m
