Answer:
The new temperature would be 705.1 K.
Explanation:
Given data:
Initial pressure = 3 kpa
Initial volume = 13 L
Initial temperature = 56.12 K
Final pressure = 70 Kpa
Final volume = 7 L
Final temperature = ?
Solution:
To solve this problem we will use the general gas equation.
P₁V₁/T₁ = P₂V₂/T₂
T₂ = P₂V₂ T₁/ P₁V₁
T₂ = 70 Kpa . 7 L . 56.12 K / 3 Kpa . 13 L
T₂ = 27498.8 / 39
T₂ = 705.1 K
