Answer: Inside the circle
5.4≅[tex]\sqrt{29}[/tex]
So any point 5.4 units away from the center or less will be inside the circle. Both [5] and [-2] are less than 5.4 units away from 0,0
The point [tex]T(5,-2)[/tex] lies inside the circle.
" A circle is defined as the two-dimensional closed curve whose all the points on the boundary are equidistant from a fixed point that is center."
According to the question,
Given,
Center of the circle [tex]= O(0,0)[/tex]
Radius of the circle [tex]= \sqrt{29}[/tex]
≈ [tex]5.4[/tex] units
Given the point,
[tex]T(5,-2)[/tex]
Point on the circle should have one of the coordinate equals to [tex]5.4[/tex].
Point outside the circle should have one of the coordinate greater than [tex]5.4[/tex].
Point inside the circle should have one of the coordinate less than [tex]5.4[/tex].
Point [tex]T(5,-2)[/tex] coordinates are less than [tex]5.4[/tex].
Hence, the point [tex]T(5,-2)[/tex] lies inside the circle.
Learn more about circle here
brainly.com/question/11833983
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