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A circle is centered at O(0,0)parenthesis and has a radius of sqrt{29}
29
​ square root of, 29, end square root.
Where does the point T(5,-2) lie? inside the circle, outside the circle or on the circle?

Respuesta :

Answer:

the point T lie on the circle

Step-by-step explanation:

[tex]OT = \sqrt{(5)^{2}+(-2)^{2} } = \sqrt{25+4} =\sqrt{29}[/tex]

Then the point T lie on the circle.

Check the attached picrude.

Ver imagen profarouk
copperdog1011

Answer:

on the circle. the proof is in the picture

Step-by-step explanation:

Ver imagen copperdog1011