Answer:
The answer to your question is: midsegment = 35 units
Step-by-step explanation:
Use the Thales' theorem
[tex]\frac{3x + 55}{6x + 5} = \frac{86}{43} \\[/tex]
43( 3x + 55) = 86( 6x + 5)
129x + 2365 = 516x + 430
129x - 516x = 430 - 2365
-387x = -1935
x = -1935 / -387
x = 5
Midpoint length = 6(5) + 5
= 30 + 5
= 35 units
