Answer:
2 imaginary; 2 real
Step-by-step explanation:
You can factor it as ...
f(x) = (x^2 -16)(x^2 +1) . . . . . . . . . x^2-16 is the difference of squares
= (x -4)(x +4)(x^2 +1)
The two linear factors have real zeros; the quadratic factor has two imaginary zeros. There are 2 imaginary and 2 real zeros.
