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An airliner is flying at 34,000 ft cruise altitude on a standard day. Calculate the pressure difference between the cabin and the atmosphere if the cabin is pressurized to an altitude of 8,000 ft. Assume standard day temperature in the cabin

Respuesta :

Answer:

[tex]\Delta P=61,952.8\ lb/ft^2[/tex]

Explanation:

Given

Airline flying at 34,000 ft.

Cabin pressurized to an altitude 8,000 ft.

We know that at standard condition ,density of air

[tex]\rho =0.074\ lb/ft^3[/tex]

We know that pressure difference    

ΔP=ρ g ΔZ

Here ΔZ=34,000-8,000  ft

        ΔZ=26,000 ft

[tex]g= 32.2\ ft/s^2[/tex]

ΔP=0.074 x 32.2 x 26,000

[tex]\Delta P=61,952.8\ lb/ft^2[/tex]

So pressure difference will be [tex]\Delta P=61,952.8\ lb/ft^2[/tex].

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