Answer:
3.62 seconds
12.67 m/s
Explanation:
t = Time taken
u = Initial velocity
v = Final velocity
s = Displacement
a = Acceleration
[tex]s=ut+\frac{1}{2}at^2\\\Rightarrow 23=0t+\frac{1}{2}\times 3.5\times t^2\\\Rightarrow t=\sqrt{\frac{23\times 2}{3.5}}\\\Rightarrow t=3.62\ s[/tex]
Time taken by ball to reach the crater floor is 3.62 seconds
[tex]v=u+at\\\Rightarrow v=0+3.5\times 3.62\\\Rightarrow v=12.67\ m/s[/tex]
The velocity of the ball at the bottom of the crater is 12.67 m/s