Answer:
Coin is dropped from a height of 19.62 m
Explanation:
We have given time t = 2 sec
As coin is drop means its initial velocity u = 0 m/sec
We have to find the height from which coin is dropped
From second equation of motion we know that
[tex]h=ut+\frac{1}{2}gt^2[/tex]
So height [tex]h=0\times2+\frac{1}{2}\times 9.81\times 2^2=19.62m[/tex]
So coin is dropped from a height of 19.62 m
