Explanation:
The given data is as follows.
Volume = 250 mL, Molarity = 0.217 M
Molar mass of [tex]ZnF_{2}[/tex] is 103.406 g/mol.
As molarity is the number of moles of solute present in liter of solution.
As, it is given that molarity is 0.217 M. This means that 0.217 moles are present in 1 liter of solution.
Therefore, number of moles present in 250 mL are calculated as follows.
[tex]0.217 \times \frac{250 mL}{1000 g}[/tex]
= 0.05425 mol
Since, number of moles equal mass divided by molar mass. Therefore, calculate the mass of [tex]ZnF_{2}[/tex] as follows.
Mass = no. of moles × Molar mass
= [tex]0.05425 mol \times 103.406 g/mol[/tex]
= 5.61 g
Thus, we can conclude that mass of zinc fluoride is 5.61 g.
