What do I fill in the boxes?

Answer:
see explanation
Step-by-step explanation:
Given
[tex]\frac{4x+1}{x^2-4x-12}[/tex] ← factorise the denominator
x² - 4x - 12 = (x - 6)(x + 2)
The fraction can now be expressed as
= [tex]\frac{4x+1}{(x-6)(x+2)}[/tex]
Split the numerator into its 2 parts, that is
= [tex]\frac{4x}{(x-6)(x+2)}[/tex] + [tex]\frac{1}{(x-6)(x+2)}[/tex]