A baseball team played 32 games and lost 8. Katy was the catcher in 5/8 of the winning games and 1/4 of nthe losing games.
a. What fraction of the games did the team win?
b. In how many games did Katy play catcher?

Respuesta :

Answer:

fraction of the games did the team win is = [tex]\frac{3}{4}[/tex]

Katy play game  = 17

Step-by-step explanation:

given data

baseball team played = 32 games

lost = 8

Katy catcher = 5/8 of winning

Katy catcher =  1/4  of losing

to find out

What fraction of the games did the team win and  how many games did Katy play

solution

we know total game = 32 and lost 8

so win is total - lost = 32 - 8 = 24

so

fraction of the games did the team win is = [tex]\frac{\frac{24}{8} }{\frac{32}{8} }[/tex]  

fraction of the games did the team win is = [tex]\frac{3}{4}[/tex]

and

so total game 24 winning is  [tex]\frac{5}{8}[/tex]

so katy winning is  [tex]24*\frac{5}{8}[/tex]

katy winning = 3 × 5 = 15

and

losing  [tex]\frac{1}{4}[/tex]

total lose game 8

so Katy  lose = 8 ×  [tex]\frac{1}{4}[/tex] = 2

so

Katy play game = 15 + 2 = 17