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he point-slope form of the equation of the line that passes through (–4, –3) and (12, 1) is y – 1 = y minus 1 equals StartFraction one-fourth EndFraction left-parenthesis x minus 12 right-parenthesis.(x – 12). What is the standard form of the equation for this line?

x – 4y = 8
x – 4y = 2
4x – y = 8
4x – y = 2

Respuesta :

calculista

Answer:

[tex]x-4y=8[/tex]

Step-by-step explanation:

we have

[tex]y-1=\frac{1}{4}(x-12)[/tex]

Convert to standard form

[tex]Ax+By=C[/tex]

where

A is a positive integer

B and C are integers

Multiply by 4 both sides to remove the fraction

[tex]4y-4=x-12[/tex]

subtract 4y both sides

[tex]-4=x-12-4y[/tex]

Adds 12 both sides

[tex]-4+12=x-4y[/tex]

[tex]8=x-4y[/tex]

Rewrite

[tex]x-4y=8[/tex]

Answer:

a

Step-by-step explanation:

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