Answer:
25.872 g of carbon dioxide will produced.
Explanation:
Given data:
mass of butane (C4H10) = 8.21 g
mass of carbon dioxide = ?
Solution:
Chemical equation
C4H10 + O2 → CO + H2O
Balanced chemical equation
2C4H10 + 13O2 → 8CO + 10H2O
First of all we will calculate the moles of butane.
number of moles = mass/ molar mass
number of moles = 8.21 g/ 58 g/mol
number of moles = 0.147 mol
from balanced chemical equation we will compare the moles of C4H10 with CO2,
C4H10 : CO2
2 : 8
0.147 : 8/2×0.147 = 0.588 moles
now we will calculate the mass of carbon dioxide from moles,
mass of CO2 = number of moles × molar mass of CO2
mass of CO2 = 0.588 mol × 44 g/mol
mass of CO2 = 25.872 g
