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To sterilize a 48.0-g glass baby bottle, we must raise its temperature from 16.0°C to 94.0°C. How much heat transfer is required?

Respuesta :

Answer:

3144.96 J

Explanation:

Heat transfer is,

[tex]q=mc\Delta t[/tex]

As we know that the specific heat of the glass is,

[tex]c=0.840J/g^{\circ}C[/tex]

Given that the mass of bottle is 48 g.

And the initial temperature is 16°C and the final temperature is 94°C.

Therefore,

[tex]q=48\times 0.840(94^{\circ}-16^{\circ})\\q=48\times 0.840\times 78^{\circ}\\q=3144.96 J[/tex]

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