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Bob is threatening Tom’s life with a giant laser with wavelength (650 nm), a distance (D = 10 m) from the wall James is shackled to. (He is still free to move along the wall.) Bob has set up a double slit experiment and Tom must figure out where to position himself such that he is at a point of destructive interference to survive. If the double slit separation is d = 5 μm, where can Tom stand to avoid a laser-full demise?

Respuesta :

Answer:

He should stand from the center of laser pointed on the wall at 1.3 m.

Explanation:

Given that,

Wave length = 650 nm

Distance =10 m

Double slit separation d = 5 μm

We need to find the position of fringe

Using formula of distance

[tex]d\sin\theta=n\lambda[/tex]

[tex]d\dfrac{y}{D}=n\lambda[/tex]

[tex]y=\dfrac{\lambda D}{d}[/tex]

Put the value into the formula

[tex]y=\dfrac{650\times10^{-9}\times10}{5\times10^{-6}}[/tex]

[tex]y=1.3\ m[/tex]

Hence, He should stand from the center of laser pointed on the wall at 1.3 m.