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If an object speeds up from a velocity of 240 m/s to 560 m/s in a time period of 10 seconds, what is the acceleration?

Respuesta :

Answer: The acceleration of the object is 32m/s^2

Explanation: Acceleration is change in velocity per unit time. The initial velocity is 240m/s and the final velocity is 560m/s. The formula for the system is a= vf-vi/t

a= 32m/s^2

aabdulsamir

Answer: 32m/s²

Explanation:

U = 240m/s

V = 560m/s

t = 10s

Acceleration = change in velocity / time

a = V - U / t

a = 560 - 240 / 10

a = 320 / 10

a = 32m/s²

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