Answer:
d) The magnitude of the spin vector along some axis is hbar/2
Explanation:
The magnitude of the spin vector is defined by the following equation: [tex]S=\sqrt{s(s+1)}\hbar[/tex]
where s = n / 2 is the spin quantum number and n can only take positive integer values. For the electron we have [tex]s=\frac{1}{2}[/tex] and [tex]S=\frac{\sqrt{3}}{2}\hbar[/tex]
On the other hand, the magnitude of S along some axis is given by: [tex]S_{i}=s_{i}\hbar[/tex]
with i=x,y,z. So, in this case we have: [tex]S_{z}=\frac{\hbar}{2}[/tex]
