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In the absence of recombination, how many genetically different types of gamete can an organism with six homologous chromosome pairs produce?

A) 6
B) 12
C) 36
D) 64
E) none of the above

Respuesta :

Answer:

(D) 64

Explanation:

We have given number of chromosome pair that is haploid number = 6

We have to calculate the number of possible gamete in absence of recombination

The number of garnets is given by [tex]2^n[/tex] where n is haploid number

In question we have given haploid number, that is n=6

So the number of gametes without recombination [tex]=2^6=64[/tex]

So option (d) is the correct answer  

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