Answer:
The distance and height of the object is 6 m and 2 m.
The image is virtual and upright.
Explanation:
Given that,
Focal length = 0.25 m
Length of image = 0.080 m
Image distance = 0.24 m
We need to calculate the distance of the object
Using formula of lens
[tex]\dfrac{1}{v}=\dfrac{1}{f}+\dfrac{1}{u}[/tex]
Put the value into the formula
[tex]\dfrac{1}{0.24}=\dfrac{1}{0.25}+\dfrac{1}{u}[/tex]
[tex]\dfrac{1}{u}=\dfrac{1}{0.24}-\dfrac{1}{0.25}[/tex]
[tex]\dfrac{1}{u}=\dfrac{1}{6}[/tex]
[tex]u=6\ m[/tex]
We need to calculate the magnification
Using formula of magnification
[tex]m=-\dfrac{v}{u}[/tex]
Put the value into the formula
[tex]m=-\dfrac{0.24}{-6}[/tex]
[tex]m=0.04[/tex]
We need to calculate the height of the object
Using formula of magnification
[tex]m=\dfrac{h'}{h}[/tex]
[tex]h=\dfrac{0.080}{0.04}[/tex]
[tex]h=2\ m[/tex]
A convex mirror produce a virtual and upright image behind the mirror.
Hence, The distance and height of the object is 6 m and 2 m.
The image is virtual and upright.
Answer:
Distance of the object = 6 m
Height of the object = 2 m
Explanation:
Thinking process:
Given that,
Focal length = 0.25 m
Length of image = 0.080 m
Image distance = 0.24 m
We need to calculate the distance of the object
Therefore, using formula of lens :
[tex]\frac{1}{u} = \frac{1}{f} + \frac{1}{u}[/tex]
[tex]\frac{1}{u} = \frac{1}{6}[/tex]
solving, gives u = 6
The magnification is calculated as follows:
m = -0.24/-6
= 0.04
The height = 2 m
The diagram yields an image behind the mirror which is upright.
