Answer:
[tex]v = 12sin400\pi t[/tex]
Given:
Voltage, [tex]v_{m} = 12 V[/tex]
frequency, f = 200 Hz
Solution:
The expression for output voltage of an AC source is given by:
[tex]v = v_{m}sin\omega t[/tex]
where
[tex]\omega = 2\pi f[/tex]
Therefore,
[tex]v = v_{m}sin2\pi f t[/tex]
Now, using the given values in the output voltage expression for an ac source:
[tex]v = 12sin2\pi \times 200 [/tex]
Thus the expression so formed is:
[tex]v = 12sin400\pi t[/tex]
