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The point-slope form of the equation of the line that passes through (–4, –3) and (12, 1) is y – 1 = y minus 1 equals StartFraction one-fourth EndFraction left-parenthesis x minus 12 right-parenthesis.(x – 12). What is the standard form of the equation for this line? x – 4y = 8 x – 4y = 2 4x – y = 8 4x – y = 2

Respuesta :

calculista

Answer:

The equation of the line in standard form is

[tex]x-4y=8[/tex]

Step-by-step explanation:

The equation of the line in point slope form is

[tex]y-y1=m(x-x1)[/tex]

we have

[tex]y-1=(1/4)(x-12)[/tex]

so

[tex]m=1/4[/tex]

[tex](12, 1)[/tex]

step 2

Find the equation of the line in standard form

The equation of the line in standard form is

[tex]Ax+By=C[/tex]

where

A is positive integer

B and C are integers

we have

[tex]y-1=(1/4)(x-12)[/tex]

Multiply by 4 both sides to remove the fraction

[tex]4y-4=(x-12)[/tex]

[tex]x-4y=12-4\\x-4y=8[/tex]

Answer:

A

Step-by-step explanation:

To simplify the first persons answer

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