Answer:
the work done by the linear spring will be equal to 23.04 k J
Explanation:
given,
k = 32 k N /m
deflected spring = 120 cm
= 1.2 m
work done by spring can be calculate as
= [tex]\dfrac{1}{2}kx^2[/tex]
= [tex]\dfrac{1}{2}\times 32 \times 1.2^2[/tex]
= 23.04 k J
hence, the work done by the linear spring will be equal to 23.04 k J
