Answer : The mass of silver chlorate will be 2.654 grams.
Explanation :
The balanced chemical reaction is,
[tex]2AgClO_3\rightarrow 2AgCl+3O_2[/tex]
First we have to calculate the moles of oxygen gas at STP.
As, 22.4 L volume of oxygen gas present in 1 mole of oxygen gas
So, 0.466 L volume of oxygen gas present in [tex]\frac{0.466}{22.4}=0.0208[/tex] mole of oxygen gas
Now we have to calculate the moles of silver chlorate.
From the balanced chemical reaction, we conclude that
As, 3 moles of oxygen produced from 2 moles of silver chlorate
So, 0.0208 moles of oxygen produced from [tex]\frac{2}{3}\times 0.0208=0.01387[/tex] moles of silver chlorate
Now we have to calculate the mass of silver chlorate.
[tex]\text{Mass of }AgClO_3=\text{Moles of }AgClO_3\times \text{Molar mass of }AgClO_3[/tex]
Molar mass of silver chlorate = 191.32 g/mole
[tex]\text{Mass of }AgClO_3=0.01387mole\times 191.32g/mole=2.654g[/tex]
Therefore, the mass of silver chlorate will be 2.654 grams.
