Answer:
Step-by-step explanation: First of all, we asume that each household recive a survey to check all health problems. After that we can sume all patients that means 32+54+78+112+96=372.
Now with a simple rule of three:
[tex]\frac{112*100%}{372}[/tex]=30.11%. We have the 30.11% of the patients have eye problems.
[tex]\frac{54*100%}{372}[/tex]=14.52%. We have the 14.52% of the patients have diabetes problems.
Answer: Our required probability would be [tex]\dfrac{83}{186}[/tex]
Step-by-step explanation:
Since we have given that
Health problems Number of patients
Obesity 32
Diabetes 54
Heart problems 78
Eye problems 112
Dental problems 96
Total 372
We need to find the probability that a person chosen at random is a diabetic patient or an eye patient.
So, P(diabetic patient) + P(eye patient)
[tex]\dfrac{54}{372}+\dfrac{112}{372}\\\\=\dfrac{54+112}{372}\\\\=\dfrac{166}{372}\\\\=\dfrac{83}{186}[/tex]
Hence, our required probability would be [tex]\dfrac{83}{186}[/tex]
