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The length of a rectangle is 3 times the width. If the length is decreased by 4 meters and the width is increased by 1 meter, the perimeter will be 66 meters. Find the dimensions if the original rectangle.

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Answer:

w is the width

L is the length

p is the perimeter

w=9

L=27

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Step-by-step explanation:

p=2[(L-4) + (w+1)]

⇔p=2[(3w-4) + (w+1)]

⇔p=2[4w-3]

⇔p=8w-6

⇔66=8w-6

⇔8w=72

⇔w=9

Then L=3w=27

:)

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