Answer:
Ve=12876.43mL : Ethanol volume
Explanation:
We apply the formula to calculate the density:
ρ=[tex]\frac{m}{V}[/tex] Formula (1)
Where:
ρ:Density in g/mL
m: mass in g (grams)
V= Volume in ml (milliliters)
We know the following data:
1L= 1000mL
Vm=Volume of mercury:VHg=0.750 L*1000mL/L=750mL
ρ-m=Density of mercury =13.546 g/mL
ρ-e: density of ethanol is 0.789 g/mL
[tex]m_{m} =m_{e}[/tex]
Development of the problem:
In formula 1 We replace the known data for the mercury :
ρ-m=[tex]\frac{m_{m} }{V_{m} }[/tex]
[tex]13.546 \frac{g}{mL} =\frac{m_{m} }{750mL}[/tex]
[tex]m_{m}=13.546 \frac{g}{mL}*750mL[/tex]
[tex]m_{m} =10159.5 g[/tex]
We know that [tex]m_{e} =m_{m} =10159.5 g[/tex], then, We replace the known data for the ethanol In formula 1:
ρ-e=[tex]\frac{m_{e} }{V_{e} }[/tex]
[tex]0.789 \frac{g}{mL} =\frac{10159.5g}{V_{e} }[/tex]
[tex]Ve=\frac{10159.5 g}{0.789 \frac{g}{mL}}[/tex]
[tex]Ve=12876.43mL[/tex]
