Explanation:
The waveform expression is given by :
[tex]y(x,t)=y_m\ sin(0.333x+5.36+585t)[/tex]...........(1)
Where
y is the position
t is the time in seconds
The general waveform equation is given by :
[tex]y(x,t)=y_m\ sin(kx+\phi+\omega t)[/tex]..........(2)
Where
[tex]k=\dfrac{2\pi}{\lambda}[/tex]
[tex]\omega=2\pi f[/tex]
On comparing equation (1) and (2) we get :
[tex]0.333=\dfrac{2\pi}{\lambda}[/tex]
[tex]\lambda=18.86\ m[/tex]
[tex]585=2\pi f[/tex]
f = 93.10 Hz
Time period, [tex]T=\dfrac{1}{f}[/tex]
[tex]T=\dfrac{1}{0.010}[/tex]
T = 0.010 s
Phase constant, [tex]\phi=5.36\ radian[/tex]
Hence, this is the required solution.
