Answer:
k=2
Step-by-step explanation:
We are given that f(x)=4x-8[/tex] and inverse of the given function
[tex]f^{-1}(x)=\frac{1}{4}x+k[/tex]
We have to find the value of k.
We have f(x)=4x-8
Let y=4x-8
Then , 4x=y+8
[tex]x=\frac{y+8}{4}[/tex]
[tex]x=\frac{1}{4}y+2[/tex]
Then ,[tex]f^{-1}(x)=\frac{1}{4}x+2[/tex]
Comparing with given inverse function then we get '
k=2
Hence, the value of k must be 2.
