Answer:
The length of third side of triangle is 4.195 feet.
Step-by-step explanation:
In a triangle as shown in the figure the law of cosines states that
[tex]a^{2}=c^{2}+b^{2}-2bccos(A)[/tex]
Since it is given that
b = 3 feet
c = 2 feet
A = [tex]140^{o}[/tex]
Using these values in the above equation we get
[tex]a^{2}=2^{2}+3^{2}-2\times 3\times 2cos(140)\\\\\therefore a^{2}=17.596\\\\a=4.195feet[/tex]
