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How much work is done by pressure in forcing 9.1 m3 of water through a pipe having an internal diameter of 15 mm if the difference in pressure at the two ends of the pipe is 2.2 atm

Respuesta :

Answer:

2022020 J

Explanation:

v = 9.1 cubic metre

Pressure difference, ΔP = 2.2 atm = 2.2 x 101000 Pa = 222200 Pa

Work done by the force in moving a distance when the distance and the force is in the same direction is given by

W = F x d

Here force is defined as

Force = Pressure difference x Area

So, W = ΔP x A x d

Here, A x d is the volume, so, the work done is

W = ΔP x V = 222200 x 9.1 = 2022020 J

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