Answer:
\mu = 41.1091, 43.6109
Step-by-step explanation:
given data sets
40.2,43.1,45.5,44.5,39.5,40.2,41.0,41.6,43.1,44.9
sample mean = (sum of all value / number of value)
sample mean = 423.6/10 = 42.36
standard deviation = 2.158 given
t =1.833 for 90% confidence interval at df = n-1 = 9
90% confidence interval is given as
[tex]\mu = mean length +\- t*\frac{s}{\sqrt {n}}[/tex]
[tex]\mu = 42.36 +\- [1.833 * \frac{2.158}{\sqrt 10}][/tex]
\mu = 41.1091, 43.6109
