Respuesta :
Answer:
The angular momentum of the particle is 58.14 kg m²/s along positive z- axis and is independent of time .
Explanation:
Given that,
Mass = 1.70 kg
Position vector [tex]r=(6.00\hat{i}+5.70 t \hat{j})[/tex]
We need to calculate the angular velocity
The velocity is the rate of change of the position of the particle.
[tex]v = \dfrac{dr}{dt}[/tex]
[tex]v=\dfrac{d}{dt}(6.00\hat{i}+5.70 t \hat{j})[/tex]
[tex]v=5.70\hat{j}[/tex]
We need to calculate the angular momentum of the particle
Using formula of angular momentum
[tex]L=r\cdot p[/tex]
Where, p = mv
Put the value of p into the formula
[tex]L=m(r\times v)[/tex]
Substitute the value into the formula
[tex]L=1.70(6.00\hat{i}+5.70 t \hat{j}\times5.70\hat{j})[/tex]
[tex]L=1.70\times34.2[/tex]
[tex]L=58.14\ kgm^2/s[/tex]
Hence, The angular momentum of the particle is 58.14 kg m²/s along positive z- axis and is independent of time .
