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Logs sometimes float vertically in a lake because one end has become water-logged and denser than the other. What is the average density of a uniform-diameter log that floats with 29.1 % of its length above water?

Respuesta :

Answer:

709 kg/m³

Explanation:

Applying the expression obtained from Archimedes Principle as:

[tex]\% of\ the\ fraction\ submerged=\frac {\rho_{object}}{\rho_{liquid}}\times 100[/tex]

Given :

Percentage of the log above water = 29.1%

Percentage of the log of the water submerged = 100-29.1 % = 70.9%

Density of water = 1000 kg/m³

So,

[tex]70.9 \% =\frac {\rho_{object}}{1000}\times 100[/tex]

The average density of the log = 709 kg/m³

ck247730

Answer to your question is 709 :)

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