Answer:
t=4.2 years
Explanation:
velocity v= 0.96c
destination star distance = 14.4 light year
According to the theory of relativity length contraction
[tex]l= \frac{l_0}{\sqrt{1-\frac{v^2}{c^2}}}[/tex]
[tex]l_0= l{\sqrt{1-\frac{v^2}{c^2}}}[/tex]
putting values we get
[tex]l_0= 14.4{\sqrt{1-\frac{(0.96c)^2}{c^2}}}[/tex]
[tex]l_0= 4.032 light years[/tex]
now distance the trip covers
D= vt
[tex]4.032\times c= 0.96c\times t[/tex]
[tex]t= \frac{4.032c}{0.96c}[/tex]
t= 4.2 years
so the trip will take 4.2 years
