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A point charge is moving with speed 2 × 107 m/s parallel to the x axis along strait line at y=2 m. At t = 0, the charge is at x = 0 m. The magnitude of the magnetic field at x = 4 m is B0 at the origin. The magnitude of the magnetic field at at origin when t = 0.15 μs is?

Respuesta :

Answer:

[tex]B_2  = 4B_1[/tex]

Explanation:

initial distance of point from the electron is r_1 = 4 m

distance moved by electron is x

x = vt

[tex]x = 2*10^{7} *0.1*10^{-6}[/tex]

x = 2 m

new distance of point from electron is r_2 = 2m

field due to moving charge is

[tex]B = \frac{ \mu_o 4vr}{4 \pi r^3}[/tex]

CHARGE IS INVERSELY PROPOTIONAL TO DISTANCE FROM ELECTRON.

therefore[tex]\frac{B_1}{B_2} = [\frac{r_2}{r_1}]^2[/tex]

                         [tex] = [\frac{2}{4}]^2[/tex]

[tex]B_2  = 4B_1[/tex]

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