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An airplane needs to head due north, but there is a wind blowing from the northeast at 50 km/hr. The plane flies at an airspeed of 700 km/hr, To end up due north, the pilot will need to fly the plane Preview degrees east of north.

Respuesta :

Answer:[tex]\theta =2.415^{\circ}[/tex]

Step-by-step explanation:

Using vector method to solve it

Resultant can be given by

[tex]R^2=700^2+40^2+2\times 700\times 40cos135[/tex]

[tex]R^2=450,408[/tex]

R=671.12 Km/hr

The angle made by resultant with 700 km/hr is [tex]\theta [/tex]

using sine rule

[tex]\frac{40}{sin\theat }=\frac{R}{sin45}[/tex]

[tex]sin\theta =0.0421509[/tex]

[tex]\theta =2.415^{\circ}[/tex]

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