Digital thermometers often make use of thermistors, a type of resistor with resistance that varies with temperature more than standard resistors. Find the temperature coefficient of resistivity (in (°C)−1) for a linear thermistor with resistances of 80.2 Ω at 0.00°C and 224 Ω at 522°C.

Respuesta :

Answer:

[tex]0.0034^oC^{-1}[/tex]

Explanation:

The temperature coefficient (α) of the resistor can be calculated as follows:

[tex] R =R_o[1+\alpha(T-T_o)][/tex]

Where, R is the resistance at temperature T, [tex]R_o[/tex] is the resistance at temperature [tex]T_o[/tex]

Substitute the values:

[tex] 224\Omega=80.2\Omega[1+\alpha(522^o C-0^oC)]\\ \Rightarrow \alpha = \frac{2.8-1}{522} = 0.0034^oC^{-1}[/tex]