Answer:
[tex]B = 7 \times 10^{-8} T[/tex]
Explanation:
As we know that charge on the plates of capacitor is changing at rate given as
[tex]i = \frac{dq}{dt} = 35 mC/s[/tex]
now this rate of charging the plates will give the displacement current in the region between the plates
Now by Ampere's law we can say
[tex]\int B . dl = \mu_0 i[/tex]
now we have
[tex]B(2\pi r) = \mu_0 i[/tex]
[tex]B = \frac{\mu_0 i}{2\pi r}[/tex]
[tex]B = \frac{2 \times 10^{-7} (35 \times 10^{-3})}{0.10}[/tex]
[tex]B = 7 \times 10^{-8} T[/tex]
