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A small sphere with a mass of 441 g is moving upward along the vertical y-axis when it encounters an electric field of 5.00 space N divided by C space i with hat on top . If, due to this field, the sphere suddenly acquires a horizontal acceleration of 13.0 space m divided by s squared space i with hat on top , what is the charge that it carries

Respuesta :

Answer:

[tex]q = 1.15 C[/tex]

Explanation:

Force on a charge particle due to external electric field is given as

[tex]F = qE[/tex]

now we know that acceleration is defined as the ratio of force and mass

[tex]a = \frac{F}{m}[/tex]

now we have

[tex]a = \frac{qE}{m}[/tex]

[tex]a = 13 m/s^2[/tex]

[tex]m = 441 g = 0.441 kg[/tex]

[tex]E = 5 N/C[/tex]

now we have

[tex]13 = \frac{q(5)}{0.441}[/tex]

[tex]q = 1.15 C[/tex]

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